Container X holds 12 litres. Container Y holds half as much as X. Container Z holds 3 litres more than Y. Which is the correct order from greatest to smallest?
Show Worked Solution
Worked Solution
Step 1: X = 12 litres.
Step 2: Y = half of X = 12 ÷ 2 = 6 litres.
Step 3: Z = Y + 3 = 6 + 3 = 9 litres.
Step 4: Order greatest to smallest: 12, 9, 6 → X, Z, Y.
Correct answer: X, Z, Y
Want more questions like this? Superholic Lab has 10,000+ MOE-aligned questions with full worked solutions.
Start Free Trial — 7 Days Free