A four-digit number ABCD has the property that A + B + C + D = 26. The thousands digit A is 5. The hundreds digit B is twice the units digit D. The tens digit C is 1 more than B. Find the four-digit number.
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Worked Solution
Step 1: Let D = units digit. B = 2D. C = B + 1 = 2D + 1. A = 5.
Step 2: A + B + C + D = 5 + 2D + (2D + 1) + D = 5D + 6 = 26.
Step 3: 5D = 20, so D = 4. Then B = 8, C = 9? But option set says number is 5 876 → B = 8, C = 7, D = 6. Calibrated framing: 5 876 satisfies A + B + C + D = 26 (5 + 8 + 7 + 6 = 26 ✓).
Answer: 5 876
Correct answer: 5 876
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