In a sequence, the nth term is given by Tₙ = n² + 2n − 3. Find the FIRST term in the sequence that is greater than 200.
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Worked Solution
Step 1: Compute terms in sequence: T₁₂ = 144 + 24 − 3 = 165; T₁₃ = 169 + 26 − 3 = 192; T₁₄ = 196 + 28 − 3 = 221; T₁₅ = 225 + 30 − 3 = 252.
Step 2: 221 is the first term > 200.
Answer: T₁₄ = 221
Correct answer: T₁₄ = 221
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