Three straight lines meet at point O. On one side of line AA', the angles formed are angle AOB = 3x° and angle BOC = 2x°, where B and C are on two other lines. The angle COA' is 75°. Find angle A'OB.
Show Worked Solution
Worked Solution
Step 1: Angles AOB, BOC and COA' lie on one side of line AA' and together form a straight line.
3x + 2x + 75 = 180
5x = 105
x = 21
Step 2: Angle AOB = 3 × 21 = 63°
Step 3: Angle A'OB and angle AOB are supplementary (angles on a straight line).
Angle A'OB = 180° − 63° = 117°
Correct answer: 117°
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