Advanced Mathematics Primary 5 Angles

Two straight lines intersect. One pair of vertically opposite angles is (4x + 5)° and (6x − 15)°. Find the size of the angle marked (4x + 5)°.

A 10°
B 45°
C 90°
D 135°
Show Worked Solution

Worked Solution

Step 1: Use the vertically opposite angles property. Vertically opposite angles are equal, so: 4x + 5 = 6x − 15 Step 2: Solve for x. 5 + 15 = 6x − 4x 20 = 2x x = 10 Step 3: Substitute x = 10 into (4x + 5)°. Angle = 4(10) + 5 = 40 + 5 = 45° Check: 6(10) − 15 = 60 − 15 = 45° ✓

Correct answer: 45°

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