HOTS Mathematics Primary 5 Area of Triangle

Rectangle ABCD has AB = 20 cm and BC = 12 cm. Point P lies on AB such that AP = 8 cm. Find the area of triangle PCD.

A 60 cm²
B 72 cm²
C 120 cm²
D 144 cm²
Show Worked Solution

Worked Solution

Step 1: Find the area of rectangle ABCD. Area = AB × BC = 20 × 12 = 240 cm² Step 2: Find PB. PB = AB − AP = 20 − 8 = 12 cm Step 3: Find the area of triangle APD. Base = AP = 8 cm, Height = AD = BC = 12 cm Area = ½ × 8 × 12 = 48 cm² Step 4: Find the area of triangle PCB. Base = PB = 12 cm, Height = BC = 12 cm Area = ½ × 12 × 12 = 72 cm² Step 5: Find the area of triangle PCD by subtracting the two surrounding triangles from the rectangle. Area of △PCD = 240 − 48 − 72 = 120 cm²

Correct answer: 120 cm²

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