Standard Mathematics Primary 5 Area of Triangle

ABCD is a rectangle with AB = 8 cm and BC = 15 cm. Point E lies on side AD such that AE = 6 cm. Find the area of triangle BCE.

A 45 cm²
B 60 cm²
C 120 cm²
D 24 cm²
Show Worked Solution

Worked Solution

Step 1: Identify base and height. Take BC as the base — it has length 15 cm. Step 2: The corresponding height is the perpendicular distance from E to line BC. Because BC is one of the rectangle's longer sides and E sits on the opposite side AD, this distance equals the rectangle's width AB = 8 cm. The position of E on AD does NOT change this height. Step 3: Area = ½ × base × height = ½ × 15 × 8 = 60 cm². Answer: 60 cm²

Correct answer: 60 cm²

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