Standard Mathematics Primary 5 Geometry

ABCD is a trapezium with AB parallel to CD. Angle DAB = 65° and angle ABC = 75°. Find angle BCD.

A 105°
B 115°
C 75°
D 145°
Show Worked Solution

Worked Solution

Step 1: In trapezium ABCD, AB ∥ CD. Line BC is a transversal cutting these two parallel lines. Step 2: Angle ABC and angle BCD are co-interior angles (between the parallel lines AB and CD, on the same side of transversal BC). Step 3: Co-interior angles between parallel lines sum to 180°: angle BCD = 180° − 75° = 105°. Answer: 105°

Correct answer: 105°

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