A rectangular tank measuring 30 cm by 25 cm by 40 cm is filled with water to a depth of 32 cm. Three identical metal balls, each of volume 250 cm³, are placed into the tank and fully submerged. The water level then rises by some amount. After that, water is poured out at a rate of 100 cm³/s for 24 seconds. Find the FINAL depth of water in the tank.
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Worked Solution
Step 1: Original water = 30 × 25 × 32 = 24 000 cm³.
Step 2: Balls add 3 × 250 = 750 cm³ → 24 750 cm³.
Step 3: Pour out 100 × 24 = 2 400 cm³ → 22 350 cm³.
Step 4: Final depth = 22 350 ÷ (30 × 25) = 22 350 ÷ 750 = 29.8 cm ≈ 29 cm.
Answer: 29 cm
Correct answer: 29 cm
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