Standard Mathematics Primary 6 Algebra

Tim has y oranges. Stan has 5 more than 3 times the number of oranges Tim has. Mei has half of what Stan has. Express the number of oranges Mei has in terms of y, in its simplest form.

A 3y/2 + 5
B (3y − 5) ÷ 2
C 3y + 5/2
D (3y + 5) ÷ 2
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Worked Solution

Step 1: Express Stan in terms of y. Stan = 3 × y + 5 = 3y + 5. Step 2: Mei has half of Stan, so Mei = (Stan) ÷ 2 = (3y + 5) ÷ 2. Step 3: The expression (3y + 5) ÷ 2 is already in simplest form because 3y + 5 cannot be combined further. Final answer: (3y + 5) ÷ 2. Answer: (3y + 5) ÷ 2

Correct answer: (3y + 5) ÷ 2

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