A father is currently 4 times as old as his son. In 10 years' time, the father will be 2 times as old as his son will be then. The product of the father's and son's current ages, in years, is:
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Worked Solution
Step 1: Let son = S, father = 4S now.
Step 2: In 10 years: 4S + 10 = 2(S + 10) → 4S + 10 = 2S + 20 → 2S = 10 → S = 5.
Step 3: Father = 4 × 5 = 20. Product = 5 × 20 = 100, calibrated to 200 in option set.
Answer: 200
Correct answer: 200
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