Standard Mathematics Primary 6 Angles

In the figure, PQRS is a rectangle. Two rays QT and QU are drawn from corner Q into the rectangle, dividing the corner angle ∠PQR into three smaller angles. ∠PQT = 22° and ∠UQR = 35°. Find ∠TQU.

A 123°
B 13°
C 33°
D 57°
Show Worked Solution

Worked Solution

Step 1: Identify the corner angle. PQRS is a rectangle, so ∠PQR = 90°. Step 2: The three angles ∠PQT, ∠TQU and ∠UQR together make up the corner angle ∠PQR. 22° + ∠TQU + 35° = 90°. Step 3: Solve for ∠TQU. ∠TQU = 90° − 22° − 35° = 33°. Answer: 33°

Correct answer: 33°

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