In a quadrilateral ABCD, ∠A = 95°, ∠B = 110°, and ∠C is twice ∠D. Find ∠C.
Show Worked Solution
Worked Solution
Step 1: Quadrilateral angle sum = 360°.
Step 2: ∠A + ∠B + ∠C + ∠D = 360°. So 95 + 110 + ∠C + ∠D = 360 → ∠C + ∠D = 155°.
Step 3: ∠C = 2 × ∠D, so 3∠D = 155° → ∠D = 51.67°, ∠C = 103.33° ≈ 104°.
Answer: 104°
Correct answer: 104°
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