In the figure, ABCD is a parallelogram. The diagonal AC is drawn. ∠ACD = 42° and ∠DAC = 33°. Find ∠BAD.
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Worked Solution
Step 1: Since AB ∥ DC, alternate interior angles formed by transversal AC are equal.
Therefore ∠BAC = ∠ACD = 42°.
Step 2: ∠BAD is split by diagonal AC into ∠BAC and ∠DAC.
∠BAD = ∠BAC + ∠DAC = 42° + 33° = 75°.
Answer: 75°
Correct answer: 75°
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