At an NTUC FairPrice promotion, the price of a laptop was first INCREASED by $20\%$, then a $15\%$ DISCOUNT was applied to the new (increased) price. After both adjustments, the final selling price was $\$1224$. What was the ORIGINAL price of the laptop?
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Worked Solution
Step 1: Let the original price be P.\n
Step 2: After a 20% INCREASE, the new price is $P \times 1.20$.\n
Step 3: After a 15% DISCOUNT on that new price, the final price is $P \times 1.20 \times (1 - 0.15) = P \times 1.20 \times 0.85$.\n
Step 4: Multiply the two factors: $1.20 \times 0.85 = 1.02$. So $P \times 1.02 = 1224$.\n
Step 5: Solve for P: $P = 1224 \div 1.02 = \$1200$.\nCheck: $1200 \times 1.20 = \$1440$; $\$1440 \times 0.85 = \$1224$. ✓
Answer: $1200
Correct answer: $1200
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